8b/b^2-4b+4

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Solution for 8b/b^2-4b+4 equation: 


D( b )

b^2 = 0

b^2 = 0

b^2 = 0

1*b^2 = 0 // : 1

b^2 = 0

b = 0

b in (-oo:0) U (0:+oo)

(8*b)/(b^2)-(4*b)+4 = 0

(8*b)/(b^2)-4*b+4 = 0

8*b^-1-4*b^1+4*b^0 = 0

(4*b^1-4*b^2+8*b^0)/(b^1) = 0 // * b^2

b^1*(4*b^1-4*b^2+8*b^0) = 0

b^1

4*b-4*b^2+8 = 0

4*b-4*b^2+8 = 0

DELTA = 4^2-(-4*4*8)

DELTA = 144

DELTA > 0

b = (144^(1/2)-4)/(-4*2) or b = (-144^(1/2)-4)/(-4*2)

b = -1 or b = 2

b in { -1, 2} 

b in { -1, 2 }

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